后端开发|Python教程
Python,读取目录所文件的文件名
后端开发-Python教程
代码： (使用os.listdir)
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复制代码 代码如下:
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import os
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def ListFilesToTxt(dir,file,wildcard,recursion):
exts = wildcard.split(" ")
files = os.listdir(dir)
for name in files:
fullname=os.path.join(dir,name)
if(os.path.isdir(fullname) & recursion):
ListFilesToTxt(fullname,file,wildcard,recursion)
else:
for ext in exts:
if(name.endswith(ext)):
file.write(name + "\n")
break
def Test():
dir="J:\\1"
outfile="binaries.txt"
wildcard = ".txt .exe .dll .lib"
file = open(outfile,"w")
if not file:
print ("cannot open the file %s for writing" % outfile)
ListFilesToTxt(dir,file,wildcard, 1)
file.close()
Test()
代码：(使用os.walk) walk递归地对目录及子目录处理，每次返回的三项分别为：当前递归的目录，当前递归的目录下的所有子目录，当前递归的目录下的所有文件。
复制代码 代码如下:
import os
def ListFilesToTxt(dir,file,wildcard,recursion):
exts = wildcard.split(" ")
for root, subdirs, files in os.walk(dir):
for name in files:
for ext in exts:
if(name.endswith(ext)):
file.write(name + "\n")
break
if(not recursion):
break
def Test():
dir="J:\\1"
outfile="binaries.txt"
wildcard = ".txt .exe .dll .lib"
file = open(outfile,"w")
if not file:
print ("cannot open the file %s for writing" % outfile)
ListFilesToTxt(dir,file,wildcard, 0)
file.close()
Test()
