1. string转const char*string s = "abc";const char* c_s = s.c_str();2. const char*转string直接赋值即可const char* c_s = "abc";string s(c_s);3. string转char*string s = "abc";char* c;const int len = s.length();c = new char[len+1];strcpy(c,s.c_str());4. char*转stringchar* c = "abc";string s(c);5. const char*转char*const char* cpc = "abc";char* pc = new char[100];//足够长strcpy(pc,cpc);strcpy(pc,cpc)是copy cpc to pc,但是遇到\0就会作为结束符结束拷贝,当cpc是包含很多个结束符时,逻辑错误,所以有的时候需要用pc = const_cast<char*>(cpc.c_str())6. char*转const char*直接赋值即可char* pc = "abc";const char* cpc = pc;7. string转char[]char str[31];cin.get(str,31)
600字范文,内容丰富有趣,生活中的好帮手!