Python 使用正则表达式匹配URL网址

(?<=href=\").+?(?=\")|(?<=href=\').+?(?=\')http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+

"^((http://)|(https://))?([a-zA-Z0-9]([a-zA-Z0-9\-]{0,61}[a-zA-Z0-9])?\.)+[a-zA-Z]{2,6}(/)"

In [1]: import reIn [2]: str = "/"In [3]: regular = pile(r'[a-zA-Z]+://[^\s]*[.com|.cn]')In [4]: re.findall(regular, str) Out[4]: ['']

很好用感谢作者

/pzk7788/p/10498128.html

import ref = open('test.txt')F = f.read()f.close()r = r'[^\.\x20\r\n\f\t]*\.apk's = re.findall(r, F)print '\n'.join(s)

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