我首先提出这个简单的方法。
开始使用简单的设置来匹配你想要的，如下面的类的关键字：如果失败介绍
@Override
protected void
onActivityResult(int requestCode, int resultCode, Intent data)
{
WordMatcher matchHello = new WordMatcher("hello");
WordMatcher matchJack = new WordMatcher("jack");
if (requestCode == VOICE_RECOGNITION_REQUEST_CODE)
{
if (resultCode == RESULT_OK)
{
List heard =
data.
getStringArrayListExtra
(RecognizerIntent.EXTRA_RESULTS);
for (String oneResult : heard)
{
if (matchHello.isIn(oneResult.split(" ")) && matchJack.isIn(oneResult.split(" "))
{
//SUCCESS!! do something here
}
}
}
else
{
Log.d(TAG, "error code: " + resultCode);
}
}
super.onActivityResult(requestCode, resultCode, data);
}
二：
public class WordMatcher
{
private Set words;
public static final int NOT_IN = -1;
public WordMatcher(String... wordsIn)
{
this(Arrays.asList(wordsIn));
}
public WordMatcher(List wordsIn)
{
//care about order so we can execute isInAt
words = new LinkedHashSet(wordsIn);
}
public Set getWords()
{
return words;
}
public boolean isIn(String word)
{
return words.contains(word);
}
public boolean isIn(String [] wordsIn)
{
boolean wordIn = false;
for (String word : wordsIn)
{
if (isIn(word))
{
wordIn = true;
break;
}
}
return wordIn;
}
过程的识别结果是这样“听起来像”匹配算法，如Soundex。
此外，您可能希望直接调查使用SpeechRecognizer类来在后台运行语音识别，而不是使用生成对话框的RecognizerIntent。
