在你们的世界里，是不是觉得程序猿一点浪漫都不懂？其实不是的，程序猿的世界也是很浪漫滴!
傻瓜版
int main(){printf("❤");return 0;}
高级版
//版本一：单个字符的心形图案#include <stdio.h>int main(void){float a,x,y;for(y=1.5f; y>-1.5f; y-=0.1f){for(x=-1.5f; x<1.5f; x+=0.05f){a = x*x+y*y-1;//这里的@符号即为打印出的心形图案符号，可更改char ch = a*a*a-x*x*y*y*y<=0.0f?'@':' '; putchar(ch); //或者putchar(a*a*a-x*x*y*y*y<=0.0f?'*':' '); }printf("\n");}return 0;}
//空心版#include <stdio.h>#include <math.h>// The first heart shape in hollow// (x^2+y^2-1)^3 - x^2*y^3 = 0// y ~ (-1.1 , 1.3 )// x ~ (-1.2 , 1.2 )int main() {for (float y = 1.3; y >= -1.1; y -= 0.06){for (float x = -1.2; x <= 1.2; x += 0.025){if (pow((x * x + y * y - 1.0), 3) - x * x * y * y * y <= 0.0)printf(" ");elseprintf("*");}printf("\n");}return 0;}
//版本二：可用多个字符组成打印#include <stdio.h>int main(void){float f, x, y, z;for (y = 1.5f; y > -1.5f; y -= 0.1f){for (x = -1.5f; x < 1.5f; x += 0.05f){z = x * x + y * y - 1;f = z * z * z - x * x * y * y * y;putchar(f <= 0.0f ? "lihuan"[(int)(f * -8.0f)] : ' ');//这里的lihuan字符可更改成符号或其他字母，汉字不行，图案会变形 }printf("\n");}return 0;}
//加颜色版
#include <stdio.h> int main(int argc, char* argv[]){float f, x, y, z;for (y = 1.5f; y > -1.5f; y -= 0.1f){for (x = -1.5f; x < 1.5f; x += 0.05f){z = x * x + y * y - 1;f = z * z * z - x * x * y * y * y;// ===================================printf("\033[47m");char buf[100] = { "lihuan" };
//这里的“lihuan”可以改为其他字符，注意，中文不行哦！if (f <= 0.0f){printf("\033[1;31m%c\033[0m", buf[(int)(f * -8.0f)]);}else{printf("%c", ' ');}printf("\033[0m");// ===================================== }printf("\n");}return 0;}
加强版：
#include <stdio.h>#include <math.h>float f(float x, float y, float z) {float a = x*x + 9.0f/4.0f*y*y + z*z - 1;return a*a*a - x*x*z*z*z - 9.0f/80.0f*y*y*z*z*z;}float h(float x, float z) {for (float y = 1.0f; y >= 0.0f; y -= 0.001f){if (f(x, y, z) <= 0.0f)return y;}return 0.0f;}int main(int argc, char *argv[]) {for (float z = 1.5f; z > -1.5f; z -= 0.05f) {for (float x = -1.5f; x < 1.5f; x += 0.025f) {float v = f(x, 0.0f, z);if (v <= 0.0f) {float y0 = h(x, z);float ny = 0.01f;float nx = h(x + ny, z) - y0;float nz = h(x, z + ny) - y0;float nd = 1.0f / sqrtf(nx*nx + ny*ny + nz*nz);float d = (nx + ny - nz)*nd*0.5f + 0.5f;putchar(".:-=+*#%@"[(int)(d * 5.0f)]);}elseputchar(' ');}putchar('\n');}}
变形版：
#include <stdio.h>int main(){int i, j, k, l, m; char c = '*'; //ASCII码里面 3 就是一个字符小爱心 for (i=1; i<=5; i++)printf("\n"); //开头空出5行 for (i=1; i<=3; i++) { //前3行中间有空隙分开来写 for (j=1; j<=32-2*i; j++) printf(" "); //左边的空格，每下一行左边的空格比上一行少2个 //8*n-2*i for (k=1; k<=4*i+1; k++) printf("%c", c);//输出左半部分字符小爱心 for (l=1; l<=13-4*i; l++) printf(" "); //中间的空格，每下一行的空格比上一行少4个 for (m=1; m<=4*i+1; m++) printf("%c", c);//输出右半部分字符小爱心printf("\n"); //每一行输出完毕换行}for (i=1; i<=3; i++) { //下3行中间没有空格 for (j=1; j<=24+1; j++) printf(" "); //左边的空格 //8*(n-1)+1for (k=1; k<=29; k++) printf("%c", c);//输出字符小爱心printf("\n"); //每一行输出完毕换行 }for (i=7; i>=1; i--) { //下7行 for (j=1; j<=40-2*i; j++) printf(" "); //左边的空格，每下一行左边的空格比上一行少2个//8*(n+1)-2*ifor (k=1; k<=4*i-1; k++) printf("%c", c);//每下一行的字符小爱心比上一行少4个（这个循环是i--） printf("\n"); //每一行输出完毕换行 }for (i=1; i<=39; i++)printf(" "); //最后一行左边的空格printf("%c\n", c); //最后一个字符小爱心 for (i=1; i<=5; i++)printf("\n"); //最后空出5行 return 0;}
#include <stdio.h>#include <math.h>#define A 3void print(void){double x,y;for(y=-4;y<=0;y+=0.3){for(x=-4;x<=4;x+=0.2)if(fabs(sqrt(x*x+y*y)-A*sin(2*atan(y/x)))<=1 ||fabs(sqrt(x*x+y*y)-A*sin(2*atan(-y/x)))<=1)printf("*");else printf(" ");printf("\n");}for(y=-1;y<=0;y+=0.2){for(x=-4;x<=4;x+=0.2)if(fabs(y)-0.65*x*x>=0.2)printf("*");elseprintf(" ");printf("\n");}}int main(void){print();getchar();return 0;}
算法链接：/HeartSurface.html
代码主要参考网址：/question/7195
