斜齿轮建模,helical gear modeling
1)helical gear modeling斜齿轮建模
英文短句/例句
1.Modeling and Stress Analysis of Helical Gear on Pro/E and ANSYS基于Pro/E和ANSYS的斜齿轮建模和应力分析
2.APDL Parametric Solid Modeling of Skew Bevel Gear Based on ANSYS基于ANSYS的斜齿锥齿轮APDL参数化建模
3.Three-dimensional Modeling of Bevel Wheel Based on AutoLISP基于AutoLISP斜齿轮的三维建模
4.Finite Element Analysis of Involute Helical Gear of Rotary Plow旋耕机斜齿圆柱齿轮的建模和弯曲分析
5.The Parameterization Design of Helical Gear based on UG基于UG的斜齿圆柱齿轮建模参数化方法
6.Behavior Modeling of Helical Gear Shaft of Gearbox Based on Pro/Engineer基于Pro/Engineer实现变速箱斜齿轮轴的行为建模
7.Study on the method of molding of parameterc for the involute helical gears based on Pro/Engineer渐开线斜齿轮Pro/E参数化建模方法研究
8.spur and helical hobbing machine正齿轮和斜齿轮滚齿机
9.Three-dimensional Modeling and Finite Element Analysis of Helical Gear based on the Actual Design Tooth Profile基于实际设计齿廓斜齿轮的三维建模与有限元分析
10.cross helical gear螺旋齿轮, 交错斜齿轮
11.A unified model was established for spur cylindrical gears, helical cylindrical gears, spur bevel gears and helical bevel gears.建立了直齿圆柱齿轮、齿圆柱齿轮、齿圆锥齿轮、齿圆锥齿轮的统一模型。
12.The Modal Analysis of Helical-Gear in Geared-Motor Based on the ANSYS基于ANSYS的减速电机斜齿轮模态分析
13.Basic tooth profile of straight and skew bevel gearsGB/T12369-1990直齿及斜齿锥齿轮基本齿廓
14.Modeling and Simulation for Tooth Face Contact Analysis of Transmission Gears;变速器齿轮齿面接触分析建模与仿真
15.Modeling Method of Straight Gears Based on AutoCAD;AutoCAD2000平台上直齿圆柱齿轮参数化建模
16.Method to Accurately Calculate Gear Tooth Stress Model齿轮齿根应力准确计算模型构建方法
17.Establishment of Mathematical Model for Involute Tooth Profile of Noncircular Gears非圆齿轮渐开线齿廓数学模型的建立
18.Accurate Modeling of the Tooth-surface of a Spiral Bevel Gear with Fillet含过渡曲面的弧齿锥齿轮齿面精确建模
相关短句/例句
gear modeling齿轮建模
3)small gear modeling小齿轮建模
4)auger gear program mode斜齿轮程序模式
5)standard bevel wheel modeling标准斜齿建模
6)gear reducer model齿轮减速器建模
延伸阅读
模塑对塑料齿轮有什么要求模塑对塑料齿轮有以下要求： 1)相互啮合的塑料齿轮用相同材科制成。 2)塑料齿轮尽量采用较大因角半径过渡，截面突变。 3)驰与孔的配合采用过渡配合而不采用过盈配合。抽与死朗固定方法如固1—16所示，其中图1—16a为袖与孔部分平面配合，图1—16b为用两个定位销固定。 4)齿轮各部分的尺寸如图1—17所示，图中各尺寸关系见公式(1—1)一公式(1—4)。 T1＞3T (1—1) H1＜H (1—2)D＝H2＞H (1—3)
