问题补充:
四边形中已知AB=BC AD=DC ∠A=55° 求∠ABC的度数
答案:
∵AB=BC AD=DC ∠A=55°
∴△ABC为等腰三角形
∴∠A=∠C = 55° 则∠B=∠D = (360° - 55°)/2 = 125 °
∠ABC = ∠B = 125 °
时间:2023-11-21 16:47:47
四边形中已知AB=BC AD=DC ∠A=55° 求∠ABC的度数
∵AB=BC AD=DC ∠A=55°
∴△ABC为等腰三角形
∴∠A=∠C = 55° 则∠B=∠D = (360° - 55°)/2 = 125 °
∠ABC = ∠B = 125 °