问题补充:
在三角形ABC中,若a/sinB=b/sinC=c/sinA,则三角形ABC形状是什么?
答案:
等边三角形a/sinB=b/sinC=c/sinA=(a+b+c)/(sina+sinb+sinc)
a/sina=b/sinb=c/sinc=(a+b+c)/(sina+sinb+sinc)
所以a/sina=b/sinb=c/sinc=a/sinB=b/sinC=c/sinA
c=b=a
时间:2024-07-07 13:07:20
在三角形ABC中,若a/sinB=b/sinC=c/sinA,则三角形ABC形状是什么?
等边三角形a/sinB=b/sinC=c/sinA=(a+b+c)/(sina+sinb+sinc)
a/sina=b/sinb=c/sinc=(a+b+c)/(sina+sinb+sinc)
所以a/sina=b/sinb=c/sinc=a/sinB=b/sinC=c/sinA
c=b=a