问题补充:
先化简,再求值:[x+2-(x-2分之5)]除以(x-2分之x-3),其中x=-2
答案:
原式=[(x+2)(x-2)-5]/(x-2)]×(x-2)/(x-3)
=(x²-9)/(x-2)×(x-2)/(x-3)
=(x+3)(x-3)/(x-2)×(x-2)/(x-3)
=x+3=-2+3=1
时间:2019-07-24 13:57:12
先化简,再求值:[x+2-(x-2分之5)]除以(x-2分之x-3),其中x=-2
原式=[(x+2)(x-2)-5]/(x-2)]×(x-2)/(x-3)
=(x²-9)/(x-2)×(x-2)/(x-3)
=(x+3)(x-3)/(x-2)×(x-2)/(x-3)
=x+3=-2+3=1
先化简再求值(X-1分之3-x+1分之1)除以x平方-1分之x 其中x=2分之1
2019-03-02