问题补充:
已知实数a,b,c满足a+b+c=-2,则当x=-1时,多项式ax5+bx3+cx-1的值是________.
答案:
1
解析分析:先把x=-1代入多项式中,可得ax5+bx3+cx-1=-(a+b+c)-1,而a+b+c=-2,再把a+b+c=-2整体代入计算即可.
解答:当x=-1时,ax5+bx3+cx-1=-a-b-c-1=-(a+b+c)-1,
∵a+b+c=-2,
∴ax5+bx3+cx-1=-(a+b+c)-1=-(-2)-1=1.
故
时间:2019-02-14 05:22:52
已知实数a,b,c满足a+b+c=-2,则当x=-1时,多项式ax5+bx3+cx-1的值是________.
1
解析分析:先把x=-1代入多项式中,可得ax5+bx3+cx-1=-(a+b+c)-1,而a+b+c=-2,再把a+b+c=-2整体代入计算即可.
解答:当x=-1时,ax5+bx3+cx-1=-a-b-c-1=-(a+b+c)-1,
∵a+b+c=-2,
∴ax5+bx3+cx-1=-(a+b+c)-1=-(-2)-1=1.
故